If the price of electrical appetite is 0.159 dollars per kilo-watt hour, what is the dollar price of regulating electrical appetite to feverishness the H2O in the swimming pool (11.8 m x 11.4 m x 1.73 m) from 13.0 to 26.7 degrees C?
What is the dollar price of regulating electrical appetite to feverishness the H2O in the swimming pool?
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Q=cm(deltaT)
Specific Heat for Water= 4186J/kg*C
Cubic Meters of Water = x1000 liters of Water = Mass in Kg
(11.8×11.4×1.73)= 232.7 m^3 =232700 liters = 232700 kg
deltaT=(26.7-13.0)= 13.7 C
4186*232,700*13.7 = 1.33E10 J
1 kWh = 3.6E6 J
1.33E10 / 3.6E6 = 3694 kWh
3694 kWh * 0.159 = $587
This regulation works, we only got it right upon my Wiley Plus
It sounds similar to we have been asking a text subject as against to a genuine universe question. In being is depends upon a outward air temperature, a wind, as good as a relations steam to establish how most of a feverishness which we have been putting in to a pool is starting to a atmosphere. If it is a balmy day there is insolation which will feverishness a H2O as well.
So it rely upon either we have been in Las Vegas or Antarctica to know either a price is $0 or infinity, since in Antarctica we have as well most feverishness detriment to keep a pool from freezing.